25-03-2023, 07:06 PM
|
471, 1372, 50653, 34328125, ?
|
|
25-03-2023, 08:04 PM
471, 1372, 50653, 34328125,...
471 = 3*157 1372 = 2*2*7*7*7 50653 = 37*37*37 34328125 = 5*5*5*5*5*5*13*13*13 _______________________________________________ d1 = 1372-471 = 901 = 17*53 d2 = 50653-1372 = 49281 = 3*16427 d3 = 34328125-50653 = 34277472 = 2^5 * 3^3 * 97 d2/d1 = r^1 (3*16427)/(17*53) = r ...(1) d3/d2 = r^2 (2^5 * 3^3 * 97)/(3*16427) = r^2 ...(2) c/d = r^2 a/b = r dividing (2) by (1) no thats not gonna work ________________________________________________________ a_n = a_1 * r^n-1 let a_1 = 471 a_2 = 1372 a_2 = 471 * r^1 1372 = 471 * r^1 ...(1) a_3 =50653 a_3 = 1372 * r^2 50653 = 1372 * r^2 ...(2) a_4 = 34328125 a_4 = 5063 * r^3 34328125 = 50653 * r^3 ...(3) dividing (2) by (1) 50653/1372 = (1372 * r^1)/471 r = (50653*471)/(1372^2) = 23857653/1882384 r = (37*37*37*3*157)/(2*2*2*2*7*7*7*7*7*7) let a_n be some f(a_n-1) on R, such that f(a_n)-f(a_n-1) = r __________________________________________________________ fuck man i give up teach me how to do it
25-03-2023, 08:40 PM
(25-03-2023, 08:04 PM)brocode Wrote: 471, 1372, 50653, 34328125,... is there even a pattern on this
25-03-2023, 08:41 PM
(25-03-2023, 08:40 PM)Lucy Wrote:(25-03-2023, 08:04 PM)brocode Wrote: 471, 1372, 50653, 34328125,... yeah its a geometric progression
25-03-2023, 10:51 PM
(25-03-2023, 08:04 PM)brocode Wrote: 471, 1372, 50653, 34328125,... a_n = xyz then a_{n+1} = y^3 * x^z in other words middle digits cubed multiplied by first digit to the power of last digit
25-03-2023, 11:12 PM
(25-03-2023, 10:51 PM)MysteriousWeeb420 Wrote:(25-03-2023, 08:04 PM)brocode Wrote: 471, 1372, 50653, 34328125,...
|
|
« Next Oldest | Next Newest »
|
Users browsing this thread:

