![]() |
|
My IQ will be unimaginably high at 100yo - Printable Version +- Lookism (https://bookism.net) +-- Forum: Lookism Forums (https://bookism.net/forumdisplay.php?fid=1) +--- Forum: Shitty Advice (https://bookism.net/forumdisplay.php?fid=2) +--- Thread: My IQ will be unimaginably high at 100yo (/showthread.php?tid=43111) |
My IQ will be unimaginably high at 100yo - MVP - 17-11-2025 Say my IQ is 100 and it increases by 1% every day. How high will my IQ be in 23000 days? We can treat this as compound growth: IQ(t)=100×(1.01)23000\text{IQ}(t) = 100 \times (1.01)^{23000}IQ(t)=100×(1.01)23000 Compute the exponent in logarithmic form to avoid gigantic numbers: ln(1.01)≈0.00995033\ln (1.01) \approx 0.00995033ln(1.01)≈0.00995033 23000×0.00995033≈228.857623000 \times 0.00995033 \approx 228.857623000×0.00995033≈228.8576 Add ln(100)=4.60517\ln(100) = 4.60517ln(100)=4.60517: ln(IQ)≈233.4628\ln(\text{IQ}) \approx 233.4628ln(IQ)≈233.4628 Convert back from natural log: IQ=e233.4628\text{IQ} = e^{233.4628}IQ=e233.4628 Convert to base 10 scale: log10(IQ)=233.46282.302585≈101.41\log_{10}(\text{IQ}) = \frac{233.4628}{2.302585} \approx 101.41log10(IQ)=2.302585233.4628≈101.41 So: IQ≈10101.41≈2.6×10101\text{IQ} \approx 10^{101.41} \approx 2.6 \times 10^{101}IQ≈10101.41≈2.6×10101 Final Answer Your IQ after 23,000 days at 1% growth per day would be roughly 2.6×10101\boxed{2.6 \times 10^{101}}2.6×10101. That is an unimaginably large number—far beyond anything physically meaningful for IQ, but mathematically that’s the result. RE: My IQ will be unimaginably high at 100yo - MVP - 17-11-2025 That is an unimaginably large number—far beyond anything physically meaningful for IQ, but mathematically that’s the result. RE: My IQ will be unimaginably high at 100yo - MVP - 17-11-2025 And thats Just If WE assume Just a 1% increase day haha RE: My IQ will be unimaginably high at 100yo - MVP - 17-11-2025 More realistic would be this: If your IQ starts at 100 and doubles every day, then after n days your IQ would be: IQ(n)=100×2nIQ(n) = 100 \times 2^{n}IQ(n)=100×2n So for 23,000 days: IQ(23000)=100×223000IQ(23000) = 100 \times 2^{23000}IQ(23000)=100×223000 This number is far beyond anything that can be written normally, but we can express it in scientific notation. ✔ Approximate Size of 2230002^{23000}223000 Use: log10(223000)=23000×log10(2)≈23000×0.30103=6923.69\log_{10}(2^{23000}) = 23000 \times \log_{10}(2) \approx 23000 \times 0.30103 = 6923.69log10(223000)=23000×log10(2)≈23000×0.30103=6923.69 So: 223000≈106923.692^{23000} \approx 10^{6923.69}223000≈106923.69 Multiply by 100 = 10210^2102: 100×223000≈106925.69100 \times 2^{23000} \approx 10^{6925.69}100×223000≈106925.69 🎯 Final Answer Your IQ would be approximately: 106925.69\boxed{10^{6925.69}}106925.69 That is a 1 followed by about 6,926 zeros. For comparison: The number of atoms in the observable universe is ~108010^{80}1080. Your “IQ” here would be incomprehensibly larger. If you want, I can express it in logarithmic form, compare it to other large numbers, or show how fast it grows visually. RE: My IQ will be unimaginably high at 100yo - hollow - 17-11-2025
RE: My IQ will be unimaginably high at 100yo - Altruist - 17-11-2025 🎯 |