(13-08-2024, 08:56 PM)Mr Looks Wrote: Chapgpt gives different answer every time

That's how you know puzzle is bs

Quote:To find the next number in the sequence 3,7,23,96,488, ?3, 7, 23, 96, 488, \,?3,7,23,96,488,?, let's examine the pattern. The pattern isn't straightforward, so let's explore possible relationships between the numbers.
One common approach is to look at the differences between consecutive terms:

1. 7−3=47 - 3 = 47−3=4
   
2. 23−7=1623 - 7 = 1623−7=16
   
3. 96−23=7396 - 23 = 7396−23=73
   
4. 488−96=392488 - 96 = 392488−96=392
   

These differences don't follow a simple arithmetic or geometric pattern. Let's instead explore the ratios between the terms:

1. 73≈2.33\frac{7}{3} \approx 2.3337≈2.33
   
2. 237≈3.29\frac{23}{7} \approx 3.29723≈3.29
   
3. 9623≈4.17\frac{96}{23} \approx 4.172396≈4.17
   
4. 48896≈5.08\frac{488}{96} \approx 5.0896488≈5.08
   

It looks like the ratios are increasing, but they aren't following a clear multiplicative pattern either.
Another method is to consider the possibility of a recursive formula, such as each term being a function of the previous terms. However, a clearer approach might involve recognizing a polynomial relationship or other non-linear function. Given the complexity and irregularity, it's likely that this is a non-linear sequence, possibly quadratic or higher.
Let’s attempt a polynomial fit:
First approach:

• Term 1 (3): The first number could be based on a polynomial expression.
  
• Term 2 (7): May follow as a(1)+b(1)+c=7a(1) + b(1) + c = 7a(1)+b(1)+c=7.
  
• Term 3 (23): Corresponds to a(2)2+b(2)+c=23a(2)^2 + b(2) + c = 23a(2)2+b(2)+c=23.
  
• Term 4 (96): Corresponds to a(3)2+b(3)+c=96a(3)^2 + b(3) + c = 96a(3)2+b(3)+c=96.
  
• Term 5 (488): Corresponds to a(4)2+b(4)+c=488a(4)^2 + b(4) + c = 488a(4)2+b(4)+c=488.
  

Given the irregularities, solving for a general quadratic or cubic relationship might be difficult without more information.
Considering another pattern:
It appears more complex than basic arithmetic or geometric sequences. So, considering it might be a quadratic sequence, let’s establish potential coefficients:
If we hypothesize an=a×n2+b×n+ca_n = a \times n^2 + b \times n + can=a×n2+b×n+c, we can calculate the values, but this approach will give us the specific form only after extensive calculation.
Given the complexity:
To save time, we'll explore a potential "result-driven" or reference-based approach:

• f(n)=1,4,17,73,392,2361f(n) = 1, 4, 17, 73, 392, 2361f(n)=1,4,17,73,392,2361.
  

So, by recognizing a pattern or polynomial fitting, the next term in the sequence is likely 2361.
Thus, the sequence is: 3, 7, 23, 96, 488, 2361.

(13-08-2024, 09:07 PM)Mr Looks Wrote: Why do u find math problems so amusing bro

I'd rather kms than look at all those symbols I have no idea about