(10-09-2024, 06:20 PM)Honest Wrote: ill discuss my method so u can point out where i went wrong


lets call the long lines (such as the left-most line in the top left rectangle) "bars"

• moving from left to right along the row, the bar moves clockwise
  
• descending the column, the bar moves anticlockwise
  
• therefore, the solution has the bar in the 9 oclock/left position
  

let's call the other lines "lines"

• when the bar is 9oclock/left, the lines begin in the center of the rectangle's y axis, and point leftwards
  
• when the bar is 3oclock/right, the lines begin in the center of the rectangle's x axis, and point upwards
  
• when the bar is 6oclock/bottom, the lines are invisible
  
• when the bar is 12oclock/top, the lines begin in the center of the rectangle's y axis, and point rightwards
  
• therefore, because the solution has the bar in 9oclock/left position, the line must begin in the centre of the rectangle's y axis, and point leftwards
  

• in the first row, the lines begin inside the rectangle
  
• in the second row, the lines begin outside the rectangle
  
• in the first two rows, the lines are the short
  
• we conclude that the type of line stays consistent across rows
  
• the line is invisible in the middle of the 3rd row due to the 6oclock/bottom bar rule
  
• we extrapolate that, because the lines stay consistent across rows, the solution (bottom right) must have a line bearing a resemblance to the bottom left rectangle
  
• therefore, the solution has a line of the same form to the bottom left rectangle
  

the updated solution is as follows:


problem is that idk why the rectangle in the middle of the matrix has a bent line. you could maybe argue that the bottommost rectangle to have a line in each column has a crooked line?

(10-09-2024, 04:12 PM)MVP Wrote: because i am god